点燃心中的火
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首先，观察其部件分布，可知春秋编钟需要2400，四足巨鼎需要1800
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再来观察事件，我就不一一举例，不管是陆地还是平原还是海上，所有事件都是500铁可得2编钟，或者500铁可得1四足巨鼎
那么此时问题就来了，事件的处理比例是编钟：巨鼎=2：1.那就意味着，只要你处理事件，当你获得1800巨鼎时，编钟必然是3600.属于溢出状态。那么要解决这个问题。就必然需要优先先拿满巨鼎
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那么一个个过来分析，第1个内陆。
可知处理第1个事件可得1个鼎
第2个事件是2个编钟
最后会送2个编钟
看到最后送的两个编钟。就直接把这个方案给pa's's了。因为在此方案中无论如何鼎都是比编钟少。
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再来看海上，其实只要看最后送的鼎和编钟的比例就知道了。同样是2个编钟1个鼎。这个方案同同样可以pa's掉。因为事件不管是平原内陆还是海上都是可以选择处理或者不处理，都可以选择处理500铁获得2个编钟或者1个顶。但是如果最后送的比例都是不平衡的状态。那么事件不管如何处理比例同样都是不平衡的。终点是2：1。事件都是2：1。想要把鼎的比例增强天方夜谭。
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最完美的就是跑平原。因为他终点的1鼎是固定的。那么就可以由此来控制两者的比例。我直接说方法。1.2事件全部用500铁做。那么加上终点可以获得2个编钟2个鼎。完美获得比例1：1。.然后同时跑到1200碎片时停止。此时编钟1200。鼎1200。然后改变方法，1事件还是用500铁，可获得2编钟。2事件放弃直奔终点，可获得1鼎。此时的比例是2编钟1鼎，继续跑600次，那么就会获得2x600次=1200编钟和600鼎。加上前面的各1200。编钟的数量就会完美=1200+1200=2400.鼎的数量也会=1200+600=1800。对应最初始的需求数量一点都不漏。
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